Companion question of https://www.scichart.com/questions/wpf/fastlinerenderableseries-handling-of-double-nan-values-where-isdigitallinetrue
We have the same issue/desire with respect to NaNs: we would like to have a similar behaviour, i.e. always render at least one point when there is a NaN. So if we have a sequence p1, NaN, p2, NaN, p3, NaN, …. the chart is not empty (like it is with LineDrawMode.Gaps) or a continuous line (like LineDrawMode.ClosedLines) but a series of points. It could be another mode like LineDrawMode.NonClosedLines or similar.
Or
Is it possible to do it by ourselves? With a CustomRenderableSeries maybe?
- Lorenzo Dematte asked 5 years ago
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Hi Lorenzo,
Thanks for your question.
Please try setting Point Markers on your line series. For more info please have a look at the following documentation article:
https://www.scichart.com/documentation/v5.x/webframe.html#The%20Scatter-Line%20Series%20Type.html
Hope this helps.
- Oleksandr Shvets answered 5 years ago
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I am considering applying server-side licensing for my javerScript application.
In the document below, there is a phrase “Our server-side licensing component is written in C++.”
(https://support.scichart.com/index.php?/Knowledgebase/Article/View/17256/42/)
However, there is only asp.net sample code on the provided github.
(https://github.com/ABTSoftware/SciChart.JS.Examples/tree/master/Sandbox/demo-dotnet-server-licensing)
I wonder if there is a sample code implemented in C++ for server-side licensing.
Can you provide c++ sample code?
Also, are there any examples to run on Ubuntu?
- Andrew Burnett-Thompson answered 5 years ago
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I think I solved it through a CustomRenderableSeries, but now I’m curious: where can I read more about ExtremeDrawingManager and how it works?
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Its just an alternative code path which we implemented to solve a few problems (like this). We don’t have any docs for this unfortunately.
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In the end I tried to use a CustomRenderableSeries based on the CustomLinesRenderableSeries you can find in the docs, and it is quite easy to get it this way.
- Lorenzo Dematte answered 5 years ago
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